Revert "Make explicit free behave the same as implicit free"

This reverts commit fc095dbedddf28ce32c711873317cf0b22579bfb.

diff --git a/lib/talloc/testsuite.c b/lib/talloc/testsuite.c
index c56cef40e0dfdab5d9e85ed10e5ea4ad5cbaa14a..3d490ddf49319139093893caff827c9fd0346bc6 100644 (file)
--- a/lib/talloc/testsuite.c
+++ b/lib/talloc/testsuite.c
@@ -784,71 +784,6 @@ static bool test_unref_reparent(void)
        return true;
 }
 
-/* If a referenced allocation is explicitly freed the new owner
-   should be the same as if the same allocation is implicitly freed
-   (because it's owner was freed).
-   Traditionally in talloc an explicit free will free the top non-child reference
-   but an implicit free will move the top (any) reference to be the new owner */
-static bool test_implicit_explicit_free(void)
-{
-       void *root, *p1, *p2, *p3, *ref, *r1;
-       int e, i;
-
-       printf("test: test_implicit_explicit_free\n# SINGLE REFERENCE IMPLICIT FREE\n");
-
-       root = talloc_named_const(NULL, 0, "root");
-       p1 = talloc_named_const(root, 1, "p1");
-       p2 = talloc_named_const(p1, 1, "p2");
-       /* Now root owns p1, and p1 owns p2 */
-
-       r1 = talloc_named_const(root, 1, "r1");
-       ref = talloc_reference(r1, p2);
-       /* now r1 has ref reference to p2 */
-       talloc_report_full(root, stderr);
-
-       CHECK_BLOCKS(__FUNCTION__, p1, 2);
-       CHECK_BLOCKS(__FUNCTION__, p2, 1);
-       CHECK_BLOCKS(__FUNCTION__, r1, 2);
-
-       fprintf(stderr, "Freeing p2\n");
-       talloc_free(p2);
-       /* how many blocks is r1 taking against p2 ? */
-       e=talloc_total_blocks(r1);
-
-       talloc_report_full(root, stderr);
-       talloc_free(root);
-
-       /* now repeat, but this time free p1 */
-       printf("test: test_implicit_explicit_free\n# SINGLE REFERENCE EXPLICIT FREE\n");
-
-       root = talloc_named_const(NULL, 0, "root");
-       p1 = talloc_named_const(root, 1, "p1");
-       p2 = talloc_named_const(p1, 1, "p2");
-       /* Now root owns p1, and p1 owns p2 */
-
-       r1 = talloc_named_const(root, 1, "r1");
-       ref = talloc_reference(r1, p2);
-       /* now r1 has ref reference to p2 */
-       talloc_report_full(NULL, stderr);
-
-       CHECK_BLOCKS(__FUNCTION__, p1, 2);
-       CHECK_BLOCKS(__FUNCTION__, p2, 1);
-       CHECK_BLOCKS(__FUNCTION__, r1, 2);
-
-       fprintf(stderr, "Freeing p1\n");
-       talloc_free(p1);
-       /* how many blocks is r1 taking against p2 ? */
-       i=talloc_total_blocks(r1);
-       talloc_report_full(NULL, stderr);
-
-       CHECK_BLOCKS(__FUNCTION__,r1, e);
-
-       talloc_free(root);
-
-       printf("success: ref1\n");
-       return true;
-}
-
 /*
   measure the speed of talloc versus malloc
 */
@@ -1197,7 +1132,6 @@ bool torture_local_talloc(struct torture_context *tctx)
        ret &= test_talloc_ptrtype();
        ret &= test_talloc_free_in_destructor();
        ret &= test_pool();
-       ret &= test_implicit_explicit_free();
 
        if (ret) {
                ret &= test_speed();